BECE JHS Mathematics 2005 Past Questions

Practice each question, then open it to see the full details.

Question 1
(a) 14 pencils × c450 = c6300;
x erasers × c300 = c6300;
x erasers = c6300/c300; x = 21
He buys 21 erasers costing c300 each with the same amount he uses to buy 14 pencils costing c450 each

(b) Circumference = 44cm; circumference = 2×π×radius; 44 = 2×22/7×radius; 44×7 = 44×radius
Radius = 44×7/44 = 7cm

(c) (2¼ - 1⅝) ÷ 3 7/16 → (9/4 - 13/8) ÷ 55/16 → (18-13/8)×16/55 = 5/8 × 16/55 = 2/11

(d) 5(n+6)/n = 1 → 5(n+6) = n → 5n+30 = n → 5n-n = -30 → 4n = -30 → n = -30/4 = -15/2
Theory
Question 4
(4a)i Simple interest = Principal×Rate×Time/100
Simple interest = c2,000,000×2×15/100
= c600,000

ii
Amount = simple interest + principal (money borrowed) = c600,000+ c2,000,000 = c2,600,000

(b)
Profit = 45%; Selling price (SP) = ??; Cost price (CP) = c2,000,000
Profit = SP-CP/CP × 100
45 = (SP-c2,000,000)/c2,000,000 × 100
45×c2,000,000 = (SP-c2,000,000)100
c90,000,000 = 100SP - c2,000,000
100SP = c200,000,000-c90,000,000; 100SP = c110,000,000
SP = c110,000,000/100 = c1,100,000
Theory