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Question 27

Simplify: 4a – 9b – 2(2a – 3b).

  • A.8a + 3b
  • B.8a – 3b
  • C.-15b
  • D.-3b
Objective

Question details

Exam body
BECE JHS
Subject
Mathematics
Year
2018
Question no.
#27
Type
Objective
Previous · Q26Simplify: 16 2 × 8 2 Next · Q28 If u= ( 3 1 ) and v= ( -2 1 ) evaluate 6v+2u.

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