Question 25i.e 3N4 = 14 = 3+4+14 7 x 2 = 14 (ii) 2N3 =10= 2 + 3 = 14 = 5 x 2 = 10 (iii) 6N2 = 16 6+2=16= 8 x 2 = 16```
Use the following in Logic for questions 48-50. NB: The Logic in question 48-50 implies that one add the first number with the second and multiply the answer by 2.
i.e 3N4 = 14 = 3+4+14 7 x 2 = 14 (ii) 2N3 =10= 2 + 3 = 14 = 5 x 2 = 10 (iii) 6N2 = 16 6+2=16= 8 x 2 = 16```
4N0 = [ ]
Objective