Question 46The ends of a diameter of a circle are (-2, 3) and (4, 7). The equation of the circle isA.x2 + y2 - 2x - 10y + 15 = 0B.x2 + y2 + 2x - 10y - 13 = 0C.x2 + y2 - 2x - 10y + 15 = 0D.x2 + y2 - 2x - 10y - 15 = 0Objective Show full explanation