the sum of 3\(\frac{7}{8}\) and 1\(\frac{1}{3}\) is less than the difference between \(\frac{3}{8}\) and 1\(\frac{2}{3}\) by:

• A.3\(\frac{2}{3}\)
• B.5\(\frac{1}{4}\)
• C.6\(\frac{1}{2}\)
• D.8
• E.8\(\frac{1}{8}\)