Question 0Find the missing numerator \(\frac{5}{x + 1}\) - \(\frac{3}{1 - x}\) - \(\frac{7x - 1}{x^2 - 1}\) = x + 1A.-1B.x - 1C.\(\frac{3(1 - 5x)}{x - 1}\)D.\(\frac{1}{(x + 1)}\)E.3(1 - 5x)Objective Show full explanation