Question 0Make T the subject of the equation \(\frac{av}{1 - v}\) = \(\sqrt{\frac{2v + T}{a + 2T}}\)A.T = \(\frac{3av}{1 - v}\)B.T = \(\frac{1 + v}{2a^2v^3}\)C.T = \(\frac{2v(1 - v)^3 - a^4v^3}{2a^3v^3 + (1 - v)^2}\)D.\(\frac{2v(1 - v)^3 - a^4 v^3}{2a^3v^ 3 - (1 - v)^3}\)E.Objective Show full explanation