y varies partly as the square of x and partly as the inverse of the square root of x.Write down the expression for y if y = 2 when x = 1 and y = 6 when x = 4

• A.y = \(\frac{10x^2}{31} + \frac{52}{31\sqrt{x}}\)
• B.y = x² + \(\frac{1}{\sqrt{x}}\)
• C.y = x² + \(\frac{1}{x}\)
• D.y = \(\frac{x^2}{31} + \frac{1}{31\sqrt{x}}\)
• E.