Question 0
In the diagram, O is the centre of the circle and POQ a diameter. If POR = 96o, find the value of ORQ.
Objective
Question details
- Exam body
- JAMB
- Subject
- Mathematics
- Year
- 1993
- Question no.
- #0
- Type
- Objective
More from this paper
- Q0Integrate \(\frac{1 - x}{x^3}\) with respect to x
- Q0change 71 10 to base 8
- Q0Evaluate \(\frac{3524}{0.05}\) correct to 3 significant figures
- Q0If 9 (x - \(\frac{1}{2}\)) 3x 2
- Q0Solve for y in the equation 10 1 x 5 (2x - 2) x 4 (y - 1) = 1
- Q0simplify \(\frac{1}{√3 - 2}\) - \(\frac{1}{√3 + 2}\)