Question 0Two perpendicular lines PQ and QR intersect at (1, -1). If the equation of PQ is x - 2y + 4 = 0, find the equation of QRA.x + 2y - 1= -0B.2x + y - 3 = 0C.x - 2y - 3 = 0D.2x + y - 1E.Objective Show full explanation