Question 0\(\frac{d}{dx} [\log (4x^3 - 2x)]\) is equal toA.\(\frac{12x - 2}{4x^2}\)B.\(\frac{43x^2 - 2x}{7x}\)C.\(\frac{4x^2 - 2}{7x + 6}\)D.\(\frac{12x^2 - 2}{4x^3 - 2x}\)E.Objective Show full explanation