A uniform bean HK of length 10m and weighing 200N is supported at both ends as shown above. A man weighing 1000N stands at a point P on the beam. If the reactions at point H an K respectively are 800N and 400N, Then the distance HP is

• A.4m
• B.3.5m
• C.3m
• D.\( 6 \frac{2}{3} \)m
• E.7m