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Question 14

solve the equation for all the positive values of 13° lens thru 360° 3tan111.2 = −1

  • A.135° or 315°
  • B.45° or 135°
  • C.315° or 45°
  • D.315° or 180°
Objective

Question details

Exam body
UNIBEN
Subject
General Paper
Year
2006/2007
Question no.
#14
Type
Objective
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