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  9. Q11
Question 11

Given log102.5 = 0.3979. evaluate log1025 + 2log10250

  • A.3.1937
  • B.4.1937
  • C.5.1937
  • D.6.1937
Objective

Question details

Exam body
UNILORIN
Subject
General Paper - Science & Engineering
Year
2012/2013
Question no.
#11
Type
Objective
Previous · Q10Evaluate (3.2) 2 - (1.8) 2 Next · Q12 Evaluate ${0.21 × 0.072 × 0.00054}/{0.006 × 1.68 × 0.63}$ correct to four…

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