Question 25

The number of atoms present in 2.5moles of a triatomic gas is equivalent to   [1mole = \(6.02\times 10^{23}\)]

  • A.\(2.5\times 10^{23}\)
  • B.\(1.5\times 10^{23}\)
  • C.\(1.5\times 10^{24}\)
  • D.\(2.5\times 10^{24}\)
Objective

Question details

Exam body
WAEC
Subject
Chemistry
Year
2017
Question no.
#25
Type
Objective

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