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Question 4

The coordinates of the centre of a circle is (-2, 3). If its area is \(25\pi cm^{2}\), find its equation. 

  • A.\(x^{2} + y^{2} - 4x - 6y - 12 = 0\)
  • B.\(x^{2} + y^{2} - 4x + 6y - 12 = 0\)
  • C.\(x^{2} + y^{2} + 4x + 6y - 12 = 0\)
  • D.\(x^{2} + y^{2} + 4x - 6y - 12 = 0\)
Objective

Question details

Exam body
WAEC
Subject
Further Mathematics
Year
2009
Question no.
#4
Type
Objective
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