Question 4The coordinates of the centre of a circle is (-2, 3). If its area is \(25\pi cm^{2}\), find its equation. A.\(x^{2} + y^{2} - 4x - 6y - 12 = 0\)B.\(x^{2} + y^{2} - 4x + 6y - 12 = 0\)C.\(x^{2} + y^{2} + 4x + 6y - 12 = 0\)D.\(x^{2} + y^{2} + 4x - 6y - 12 = 0\)Objective Show full explanation