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Question 9

The equation of a circle is \(3x^{2} + 3y^{2} + 6x - 12y + 6 = 0\). Find its radius

  • A.1
  • B.\(\sqrt{3}\)
  • C.\(\sqrt{11}\)
  • D.\(\sqrt{6}\)
Objective

Question details

Exam body
WAEC
Subject
Further Mathematics
Year
2011
Question no.
#9
Type
Objective
Previous · Q8Solve \(3x^{2} + 4x + 1 > 0\) Next · Q10 \(f(x) = p + qx\), where p and q are constants. If f(1) = 7 and f(5) = 19, find…

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