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Question 8

Solve the equation: 3a + 10 = a\(^2\)

  • A.a = 5 or a = 2
  • B.a = -5 or a = 2
  • C.a = 10 or a = 0
  • D.a = 5 or a = 0
  • E.a = 5 or a = -2
Objective

Question details

Exam body
WAEC
Subject
Mathematics
Year
1991
Question no.
#8
Type
Objective
Previous · Q7Factorize 3a\(^2\) - 11a + 6 Next · Q9 Simplify \((\frac{3}{x} + \frac{15}{2y}) \div \frac{6}{xy}\)

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