Question 2If sin\( \theta \) = K find tan\(\theta\), 0° \(\leq\) \(\theta\) \(\leq\) 90°.A.1-KB.\( \frac{k}{k - 1} \)C.\( \frac{k}{\sqrt{1 - k^2}} \)D.\( \frac{k}{1 - k} \)E.\( \frac{k}{\sqrt{ k^2 - 1}} \)Objective Show full explanation