Question 19

If \(tan x = \frac{1}{\sqrt{3}}\), find cos x - sin x such that \(0^o \leq x \leq 90^o\)

  • A.\(\frac{\sqrt{3}+1}{2}\)
  • B.\(\frac{2}{\sqrt{3}+1}\)
  • C.\(\frac{\sqrt{3}-1}{2}\)
  • D.\(\frac{2}{\sqrt{3}-1}\)
Objective

Question details

Exam body
WAEC
Subject
Mathematics
Year
1999
Question no.
#19
Type
Objective

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