Question 10Make p the subject of the relation: q = \(\frac{3p}{r} + \frac{s}{2}\)A.p = \(\frac{2q - rs}{6}\)B.p = 2qr - sr - 3C.p = \(\frac{2qr - s}{6}\)D.p = \(\frac{2qr - rs}{6}\)Objective Show full explanation