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Question 10

Make p the subject of the relation: q = \(\frac{3p}{r} + \frac{s}{2}\)

  • A.p = \(\frac{2q - rs}{6}\)
  • B.p = 2qr - sr - 3
  • C.p = \(\frac{2qr - s}{6}\)
  • D.p = \(\frac{2qr - rs}{6}\)
Objective

Question details

Exam body
WAEC
Subject
Mathematics
Year
2012
Question no.
#10
Type
Objective
Previous · Q9Simplify: \(\frac{54k^2 - 6}{3k + 1}\) Next · Q11 If x + y = 2y - x + 1 = 5, find the value of x

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