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Question 21

Given that cos 30\(^o\) = sin 60\(^o\) = \(\frac{3}{2}\) and sin 30\(^o\) = cos 60\(^o\) = \(\frac{1}{2}\), evaluate \(\frac{tan 60^o - q}{1 - tan 30^o}\)

  • A.\(\sqrt{3 - 2}\)
  • B.2 - \(\sqrt{3}\)
  • C.\(\sqrt{3}\)
  • D.-2
Objective

Question details

Exam body
WAEC
Subject
Mathematics
Year
2017
Question no.
#21
Type
Objective
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