Question 29

Make x the subject of the relation d = \(\sqrt{\frac{6}{x} - \frac{y}{2}}\)

  • A.x = \(\frac{6 + 12}{d^2 + y}\)
  • B.x = \(\frac{12}{d^2 - y}\)
  • C.x = \(\frac{12}{y} - 2d^2\)
  • D.x = \(\frac{12}{2d^2 - y}\)
Objective

Question details

Exam body
WAEC
Subject
Mathematics
Year
2017
Question no.
#29
Type
Objective

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