Two capacitors C₁ and C₂ are connected as shown in the diagram. The capacitance C₂ is twice C₁ when the key is opened the energy stored up in C₁ is W. If the key is later closed and the system is allowed to attain electrical equilibrium, the total energy stored in the system will be

• A.\(\frac{1}{2}\)W
• B.\(\frac{2}{3}\)W
• C.W
• D.2w
• E.3W