Question 8

A body is projected with an initial velocity U at an angle O to the horizontal. The time taken by it to reach its maximum height is given by the expression

  • A.\(\frac{2u \text{sin}\theta}{g}\)
  • B.\(\frac{u^2 \text{sin}^2\theta}{2g}\)
  • C.\(\frac{u \text{sin}\theta}{g}\)
  • D.\(\frac{u \text{sin}\theta}{2g}\)
Objective

Question details

Exam body
WAEC
Subject
Physics
Year
2015
Question no.
#8
Type
Objective

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