Question 1

(a) If p varies directly as \(r^{2}\) and p = 3.2 when r = 4, find the value of p when r = 6.5.

(b) Solve the simultaneous equations :

\(\frac{x}{2} + \frac{y}{4} = 1 ; \frac{x}{3} - \frac{y}{4} = \frac{-1}{6}\)

Theory

Question details

Exam body
WAEC
Subject
Mathematics
Year
2003
Question no.
#1
Type
Theory

More from this paper

See all Mathematics 2003 questions