Question 3

(a) Simplify : \(625^{\frac{3}{8}} \times 5^{\frac{1}{2}} \div 25\)

(b) Solve the following equations correct to one decimal place. 

(i) \(\tan (\theta + 25)° = 5.145\)

(ii) \(5\cos \theta - 1 = 0\), where \(0° \leq \theta \leq 90°\).

Theory

Question details

Exam body
WAEC
Subject
Mathematics
Year
2003
Question no.
#3
Type
Theory

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